Why can’t I use google test’s ASSERT_TRUE for my SFINAE check?

  c++, googletest, sfinae

I have a simple SFINAE check for the existence of a static member function using C++17’s std::void_t:

template <class T, class X = void>
struct has_bar {
    static const bool value = false;
template <class T>
struct has_bar<T, std::void_t<decltype(T::bar(std::declval<int&>()))>> {
    static const bool value = true;

The class Foo obviously has a bar member function taking an int& as its only argument, the class NoBar has no such member function:

struct Foo
    static void bar(int& value)
        value = 42;

struct NoBar{};

Using has_bar in a static_assert works as expected, but using it in an ASSERT_TRUE statement yields a compiler error:

TEST(SFINAE, has_bar)

    //why does this not work??

int main(int argc, char** argv)
    ::testing::InitGoogleTest(&argc, argv);
    return RUN_ALL_TESTS();
ASM generation compiler returned: 0
/opt/compiler-explorer/gcc-10.2.0/bin/../lib/gcc/x86_64-linux-gnu/10.2.0/../../../../x86_64-linux-gnu/bin/ld: /tmp/ccfSP5vL.o: in function `SFINAE_has_bar_Test::TestBody()':
/home/ce/<source>:42: undefined reference to `has_bar<Foo, void>::value'
collect2: error: ld returned 1 exit status
Execution build compiler returned: 1

Is this a google test bug or am I missing something here?

Source: Windows Questions C++