I couldnt find any solution, so Im posting a new topic. I have to use accumulate with a const function as a parameter (doing some practice for a test): get_skills() – returns a list of skills and is defined as: const vector<string>& get_skills() const; I have to return a sum of the lengths of all ..
Category : accumulate
When i am coding the code below, i am getting a negative sum (-294967296). #include<iostream> #include<vector> #include<numeric> using namespace std; int main() { vector<long long int> v={1000000000 , 1000000000 , 1000000000 , 1000000000}; cout<<"Sum of all the elements are:"<<endl; cout<<accumulate(v.begin(),v.end(),0); } but when i am coding the code below i am getting a positive sum ..
The result of the following code is very surprising to me. Why does using accumulate produce such a large error? I know that because it is single precisions, it will have a round-off error but when using reduce without any policy (single precision), this round-off error is not so significant! In fact, round-off errors is ..
Is this the only solution when there is a pointer that points to a vector and we would like to use accumulate to sum up numbers? Is there any simpler solution rather than writing a lambda function and using a four argument type of accumulating? Also, for using std::sort, will the situation be the same? ..
This program: #include <ranges> #include <numeric> #include <iostream> int main() { auto rng = std::ranges::istream_view<int>(std::cin); std::cout << std::accumulate(std::ranges::begin(rng), std::ranges::end(rng), 0); } is supposed to sum up all integers appearing as text on the standard input stream. But – it doesn’t compile. I know std::ranges::begin() and std::ranges::end() exist, so what’s going on? The compiler tells me ..
vector<int> nums={1,12,-5,-6,50,3}; int k=4; int n=nums.size(); for(int i=0;i<=n-k;i++) cout<<accumulate(nums.begin()+i,nums.begin()+i+k-1,0)<<" "; The output of the above code is: 8 1 39 The question is why sum of [1,12,-5,-6] is 8, which should be 2=(1+12-5-6) ? Same for 1, which should be 51=(50+12-5-6), and Same for 39, which should be 42=(50+3-6-5)? Source: Windows Que..
I am trying to calculate the average of the entries, but for some reason I am getting an unexpected error: error: no match for ‘operator+’ (operand types are ‘double’ and ‘const OrderBookEntry’) __init = __init + *__first;" ~~~~~~~^~~~~~~~~~ I am new to C++ and tried to solve this for a while, but nothing worked. int ..
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