#### Category : alignment

While reading beginner material/tutorials relevant to lock-free programming (and after doing some exercises) I found this happening. Given the following piece of code (where the only difference is pretty much using alignas(64) in struct node2 while manually "aligning" in struct node1) #include <mutex> #include <benchmark/benchmark.h> struct node1 { node1* next{ nullptr }; int value{ 0 ..

In https://en.cppreference.com/w/cpp/memory/align, there’s a space parameter that’s the "buffer size." What is meant by buffer size here? Is it like the amount of space you have to use to create the designed alignment? If it is, why is it needed? Source: Windows Que..

I know what aligning a pointer means. I believe "size" here means the size of the memory to be occupied by the object in which the pointer is pointing to. But you’re also given an "alignment" variable. What is the meaning of this variable? In this context, is it simply the value in which you ..

I’m trying to understand how this alignment works. It should align an uint32 address to its nearest 8 byte aligned address static inline uint32_t ZBI_ALIGN(uint32_t n) { return ((n + ZBI_ALIGNMENT – 1) & -ZBI_ALIGNMENT); Let’s take n=10, and ZBI_ALIGNMENT=8. The nearest address should be 16 returns ((10 + 8 -1) & -8) = 17 ..

I am trying to write some c++ code which is crucial for performance. Therefor I am using AVX intrinsics and need to align my data to 32 byte. I am using a struct which look similar to this: (I commented out parts of it to track down the issue) struct Summation { alignas(ALIGNMENT) float summation[HIDDEN_SIZE] .. I am trying to calculate a morph offset for a gpu driven animation. To that effect I have the following function (and SSBOS): layout(std140, binding = 7) buffer morph_buffer { vec4 morph_targets[]; }; layout(std140, binding = 8) buffer morph_weight_buffer { float morph_weights[]; }; vec3 GetMorphOffset() { vec3 offset = vec3(0); for(int target_index=0; target_index < target_count; ..

Given the following C++ class: class X { public: uint8_t a; uint32_t b __attribute__ ((aligned(32))); }; How can the compiler ensure that the storage for b is 32-byte aligned, when an instance of X is presumably word-aligned? Does the aligned attribute only specify alignment relative to the object instance start address? If so, what is ..