Why do these loops give the same output: #include<iostream> #include<vector> using namespace std; int main() { vector<int> ar = {2, 3 ,4}; for(auto i: ar) //this line changes in the next loop cout<<i<<" "; cout<<"n"; for(auto &i: ar) //i changed to &i cout<<i<<" "; } They both give the same output: 2 3 4 2 ..
Category : ampersand
In the main function, we have the second line Node *head=&n1; So my question is, the head of a node is for data, not for address, so why is address stored in head of n1 node? Source: Windows Que..
what I want from second_pointer is to point to the address passed directly into it, but the error is Segmentation fault (core dumped) Why ? short i {} ; short* pointer { &i} ; LOG " address of variable : " << pointer ; short* second_pointer = (short*) 0x7ffe8475245e ; LOG " value pointed by ..
I came across some C++ code which looks roughly like this: void (classA::*methodA)() const noexcept { &classA::methodB }; Note: obviously I’m abstracting out the class name and method names in this example. What is the purpose of methodA? Analysis of the code It appears to be referencing methodB, but without parentheses, so it doesn’t appear ..
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