Category : arithmetic-expressions

int main() { int a=5,b=-7,c=0,d; d= ++a && ++b || c++; cout<<a<<"t"<<b<<"t"<<c<<"t"<<d<<"n"; int x = 1,y =0,z=5; int e = x&&y||z++; cout<<x<<"t"<<y<<"t"<<z<<"t"<<e<<"n"; int f = x&&y&&z++; cout<<x<<"t"<<y<<"t"<<z<<"t"<<f<<"n"; int g = x&& y&& ++z; cout<<x<<"t"<<y<<"t"<<z<<"t"<<g<<"n"; int h = x&& y|| ++z; cout<<x<<"t"<<y<<"t"<<z<<"t"<<h; return 0; } //***OUTPUT*** // 6 -6 0 1 // 1 0 6 1 ..

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The program is meant to convert a USD($) quantity inputted by the user (from $0 to $10 max) and output it in quantities of quarters, dimes, nickles, and pennies. #include <iostream> const double QUARTER {0.25}; const double DIME {0.10}; const double NICKLE {0.05}; const double PENNY {0.01}; void dollarToCoin(double cash, unsigned short& quarters, unsigned short& ..

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I wonder, why functional objects in c++ are implemented as templated, with void as default type since c++14. For example: https://en.cppreference.com/w/cpp/utility/functional/plus https://en.cppreference.com/w/cpp/utility/functional/minus This object in fact performs arithmetic operation +, -, *, /, when called by operator(). The operator() has to be template to work with different types as arguments, but why does the struct ..

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