I want to concatenate the path of a directory which is "/sdcard/hello.txt", but my problem is the first half(/sdcard) is defined in #define format and 2nd is const char *file_path("/hello.txt") which I am taking from the user. So to make a full path I have to concatenate these two halfs to make a full path ..
Category : char
How to check if char is equal to ‘∙’ (special character)? It seems int(my_char) == int(‘∙’) does not work. C++ preferred. Source: Windows Que..
it gives the exception in this function std::string string_re(std::string number, int start){ std::string ret = ""; for(int index=start; index != start+13; index++){ const char val = number[index]; // this line std::string s(1, val); ret += val; } return ret; } std::string number = "73167176531330624919225119674426574742355349194934" "96983520312774506326239578318016984801869478851843" "85861560789112949495459501737958331952853208805511" "12540698747158523863050715693290963295227443043557" "66896648950445244523161731856403098711121722383113"; string_re(number, 0); It just writes an exception ..
When I declare std::vector<std::string> v, i can easily check if it contains given char sequence if ( std::find( v.begin(), v.end(), "abc" ) != v.end() ) { // some logic if contains } but if i use std::vector<const char*> v and try to apply the same logic to find given char sequence my code does not ..
Is the following snippet of code safe? It invoked std::string’s fourth constructor that takes in a pointer to a null terminated string. The thing is, I’m not sure if word below is null terminated. Is it? std::array<char, 4> word{‘a’, ‘b’, ‘c’, ‘d’}; int main() { std::string p = word.data(); return 0; } Source: Windows Questions ..
Can Someone explain me what this line of code means -(char)((unsigned char) ~0 >> 1) – 1); I don’t know why the writer used a " – " in front of char and the -1 in last. I know that the ~0 will turn all the bits to 1 and then right shift will shift ..
I am doing a class project for a banking system. One of the tasks is to make sure that a user doesn’t enter a numerical character when putting in their name, and vice versa when putting in say, DOB, and or phone number. I am using a char array to get first and last name, ..
My program contains a method for reading a file (, which hold information about the different gamemap tiles). It starts by opening the file and then it reads through all the lines. The reading of the lines starts by checking if the first character is "|" and if it’s true, it continues to the next ..
Here I have a struct operator: typedef struct operator{ char symbol; uint8_t precedence; uint8_t assoc; uint8_t type; op(char s, uint8_t p, uint8_t a, uint8_t t){ symbol = s; precedence = p; assoc = a; type = t; } } op; However, in the constructor, the first parameter of type char yields the error expected an ..
char* s = "123"; std::cout << s[s[3]] << std::endl; // prints 1 std::cout << s[3] << std::endl; // prints nothing? I tried running the following snippet and the first print statement outputs 1 while the second outputs (seemingly) nothing. What is going on when the pointer is dereferenced using the length of the char pointer ..
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