I want to extract just decimal part as a integer but it wasn’t that easy as I thought. While searching I found that float/decimal aren’t the things that we can trust upon. Is floating point math broken? Here I got answer why they don’t work as expected but how exactly can I get decimal part ..

#### Category : floating-point

I have a snippet of code that compute the sum of two squared floats: float a, b, c; // assign some random float to b and c a = b*b+c*c; Can a, the sum of the two squared floats, be negative? Source: Windows Que..

I need to find out the exact binary representation for floats and doubles in a C++ project built with Platformio for an Atmega328 using the Ardurino framework. I don’t have access to the actual hardware so I can’t check it myself. The micro does not have an FPU and is 8 bit so it’s pretty ..

I’m learnig to use the Google Test framework. I set up a simple class for training. The corresponding EXPECT_EQ() fails, although they are the same value. Why is that? I know, how I use the object in the test is inefficient and gtest provides better functionality to test classes, but I wanted to simply test ..

Code: #define N 4 float unknowns[N] = {71/129, 539/1461, 1493/8507, 17/33}; for(int i = 0; i < N; i++) { cout << unknowns[i] << " "; } cout << endl << endl; Output: 0 0 0 0 For some reason the program is outputing the numbers in the array as integers and not as floats ..

I already know how floating point numbers stored in memory and I understand why expression 0.1 + 0.2 != 0.3 is True. But I don’t understand why 0.2f + 0.3f == 0.5f is true. Here is my code: cout << setprecision(64) << "0.3 = " << 0.3 << "n" << "0.2 = " << 0.2 ..

In C and C++, we all know that converting a floating point value into an integer performs a truncation. That means, a fix towards zero, both for static_cast and for C style casts. static_assert(static_cast<int>(2.9) == 2); static_assert((int)-3.7 == -3); To convert a floating point number into an integer, there are 4 options, each of them ..

I would like to represent a double as a string, without any extra 0s or without any rounding losing any its significant digits. Ignoring minor errors due to the nature of floating point.. e.g. when it might have a bunch of 0s after the last really useful digit with a 3 tacked on the end.. ..

I am facing trouble while evaluating expression "590 + 9.077236 + 3673.126 + 34787.3284 – 0.99347 * 872367" in my c++ code. How to evaluate expressions having floating numbers. for ex "11.256 + 25.336*56.566 + 36.256" Source: Windows Que..

#include <iostream> #include namespace std; int main() { float myNum = 60/(60*60); cout << myNum; return 0; } The code above gives an an output of 0 instead of the expected 0.016666667 which you get from a regular calculator. Source: Windows Que..

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