The problem states to print the number of bit strings possible of size n. Mathematically, the answer is just 2^n but because n can be from 1 to 10^6, the answer must be a data type of larger size. Here is my program: #include <bits/stdc++.h> using namespace std; using ll = long long; using ull ..

#### Category : integer-overflow

I created the following code for finding the answer to the coin problem. This involves finding minimum number of coins of given k denominations (where each such coins are in infinite supply) to form a target sum n. In particular I have investigated the case where k=5, denominations = {2,3,4,5,6} and target sum n=100. Code: ..

I made a simple function that I called symmetricDelta() which calculates the delta between value and previous "symmetrically". What I mean by that is: consider a number-line from e.g. 0 to ULLONG_MAX, where you connected the left and right ends of the number-line… To determine a "symmetric" delta, assume the change is positive if value ..

The full question fits the title. Here’s a quick example: constexpr int increment(int const value) /*noexcept?*/ { return value + 1; } As far as I know, noexcept should be interpreted as “nofail” when deciding whether to mark a function with it or not. Therefore, no possible situation for throwing isn’t the only reasoning which ..

From updating clang to 10 this code now gives implicit conversion warnings. This is for parsing JSON and since JSON works with JavaScript, and JavaScript has loose conversion rules I’m not sure how to deal with the overflow properly. Is this a situation where I want to disable the warning, or should I make the ..

FormatDateTime – Integer arithmetic overflow C++ I’m using a C++ builder function which allows me to format a time received from my microcontroller as below: void DisplayTime(unsigned long SecondsSince1900, unsigned short FractionOfSecond, AnsiString* DecodedString) { TDateTime WindowsDate; double FloatingDate; FloatingDate = SecondsSince1900 + (FractionOfSecond / 65536.0); if ( (SecondsSince1900 & 0x80000000) == 0 ) {// ..

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