#### Category : sqrt

#include <iostream> float calculating_root(float N, float root_N, float increment) { int safety=1; while(safety==1) { if (N == (root_N*root_N)) { safety=0; return root_N; } else if(N<((root_N+increment)*(root_N+increment))) { safety=0; return calculating_root(N,root_N, increment*0.1); } root_N=root_N+increment; } } int main() { float N, root_N=0.0, increment=1000.0; scanf("%f",&N); float x = calculating_root(N, root_N, increment); printf("n%gn",x); return 0; } I’ve been thinking ..

What’s wrong? How to calculate the logarithm in this function? How to do input validation? How do I check for negative exponents? Why does the function exist when the logarithm is negative, but the code does not recognize it? I put restrictions on the negative logarithm, but the function for negative values ​​of the logarithm ..

I need to evaluate the expression cbrt(b) / ((b)^2 + 1). If b less than zero, the log is not correct and outputs an incorrect answer. For example, if the input is -3 the answer is y = -1IND. #include <iostream> #include <cmath> int main() { float b, y, y1, y2; std::cout << "The equation: ..

C++ I need to evaluate the expression cbrt(b) / ((b)^2 + 1) if ‘b’ is only negative number log is not competent { y1 = cbrt(b); y2 = pow(b,2) + 1; y2 = 1 / y2; y = y1 * y2; cout << "y = "<< y << endl; } Source: Windows Que..

As a matter of curiosity, why are std::sqrt and std::pow overloaded just for a single type of parameter? Why are they not implemented as function/functor templates? Source: Windows Que..

In C++, is there a compile-time way to compute the largest value of an integral type T that can be safely squared, i.e. that mathematically x * x <= std::numeric_limits<T>::max() so that if the operation x*x were to be performed, it would not cause undefined behavior (for signed types) or overflow (for unsigned types? I’m ..